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However at LHC protons are used not electrons. Protons have a diameter of about 10^(-15)m. Of course not the protons, but the quarks and at LHC even mainly the gluons are colliding.
For the non-experts, the following picture is an illustration of a proton by the Oxford Hera group's website.
The dots are quarks. In a proton quarks minus antiquarks net 3 quarks. The springs represent gluons. The lower energy you count the more gluons are there. These are the "force particles" of the strong interaction, which holds as well nuclei together, and have the interesting property that they carry as well strong charge.
The best known "force particle" is the photon, which is the carrier of the electromagnetic interaction. Others are gravitons (not yet directly observed, but who doubts they exist), and the W (Z) bosons, the carrier of the weak interaction, which are the only force particles known which have mass. Der Amerikaner ist die Orchidee unter den MenschenVolker Pispers
Then again, the "radius" of a wavefunction, be it the electron orbital in an atom or the wf of a quark in the proton, is only meaningful as an order of magnitude anyway. We have met the enemy, and he is us — Pogo
But more important you have a typo "but a quark is a composite particle containing three quarks", should be proton is a composite particle... Der Amerikaner ist die Orchidee unter den MenschenVolker Pispers
I suppose I could find it in the particle data booklet, but can you outline the experiment that tests the electron radius? We have met the enemy, and he is us — Pogo
I don't know what measurement exactly provides the best measurement, could be a precision measurement of the B sector or whatever, but that's it pretty much. Der Amerikaner ist die Orchidee unter den MenschenVolker Pispers
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